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24x^2-26x^2+9x-1=0
We add all the numbers together, and all the variables
-2x^2+9x-1=0
a = -2; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·(-2)·(-1)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{73}}{2*-2}=\frac{-9-\sqrt{73}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{73}}{2*-2}=\frac{-9+\sqrt{73}}{-4} $
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